Friday, 31 December 2010

偽.SIMC回憶錄3.2

6:45, Day 3, NUS high school
今天是繳交written report的日子,我們要做的事就是把昨晚做出來的內容文字化交出去而已。有電腦,有MS word,我們以為要打一份報告十分容易,其實不然。
一台手提電腦,缺掉滑鼠,其機動性就好像減了一半。特別是針對給定的地圖上畫畫作出解釋,這對我們難度十分高,要用手提電腦的觸控版實在太難了。
不過,要說到港人還有甚麼優點的話,那就是夠快了。答案是在昨晚figure out,至於要怎樣下筆,則從來沒有想過。所謂的報告應該有格式無格式,還是好像公開試那樣寫上題號就能作答?我也不知道。但真正坐在電腦前方,身邊的一切就在這一瞬間凝固掉,身處一間沒冷氣室溫三十五度的房間也好,隔壁的中國隊無聊得在跳舞也好,我們唯一看到就是眼前的文件。 (這倒有點像HKMO, 聖賢之類的團體賽,能幾個人圍在一起計一題數的情況真少見)
於是,很快地,這份報告就像一份第一堂收的功課一樣被趕起了。沒有多餘的修飾,只有簡陋的說明圖;沒有華麗的算式,只有簡單直接的解釋。
……
正午是報告的截數時間,從十時開始趕工,到最後我們早了三十分鐘交出來,可說是不錯的速度了。不過,書面報告之後,還有一項更剌激的,就是口述報告。
在第四日早上,我們會隨機被分到四位評審,我們要分四次單獨的解釋我們的報告。在這種問題下,排除窮舉外幾乎沒有「絕對正確」的答案,因為這部分最刺激的地方在於評審有權隨時打斷你的發言來質問你(原則上,Q&Asection是最後五分鐘,但事實上顯然不是)。
此時我們開始預備簡報,問題是,我們的解答中,證明了幾個直觀排列「是開店的必然法則」來證明我們的答案。很可惜,當地圖越來越複雜時,一間店身處於某座標時不能同時滿足所有的必然法則,在「開店開小化」下我們顯然不能滿足所有法則,那在直觀排列下的可能答案就不止一個了。窮舉顯然不是很好的辦法。

晚上我們暫停了手上的工作,選擇了跟各國選手比試一下--當然不是數學,我們選擇了另一種全場通用的語言--體育作為切磋的部分。雖說是比賽途中,但每個人就輕鬆得像在學校跟隊打一樣,我們就這樣渡過了一晚。
順帶一提,這天晚上的食物是類似炒年糕的東西,再配以炸魷魚(煎炸炒,很地道的煮法?),但最神奇的是前幾天桃紅色的賓治被稀釋成淺紅色,據說有人服用後腸胃不適……
不過把雜果賓治撇開後,能夠在同一個地方幾天內吃到各國的美食也算是不錯……(你說甚麼?香港也能吃到上述各國地道食物?這點我也不得不承認,但我在這裡是衷心覺得他們安排不錯的呢。)

這晚沒有英超,我們卻再次聚到同一開房裡開通宵,將那萬惡的簡報預備好,然後爭取為數不多的寶貴休息時間。
……

Wednesday, 29 December 2010

Economics : Inflation

Inflation

It’s the persistent increase in general price level, while deflation is the persistent decrease in general price level. The followings are not included as inflation:

1) Temporary rise in price level (e.g. during Festival, weather)

2) Once-and-for-all (only one time) rise in general price level (e.g. imposes of tax)

3) Persistent rise in the price of a single good

Inflation or deflation rate = %ΔPI = (PI2-PI1)/PI1 * 100%

Nominal value (money value) is the value (in terms of money) in the period. Larger general price level implies smaller purchasing power per unit of nominal value.

Real value implies the value in terms on money in the base period. It implies purchasing power directly. Real and nominal values are related by:

Real value = Nominal value in a specified period/PI in that period * 100

Nominal interest rate (n) is the rate of change in nominal value of an asset over a specified period of time. Real interest rate (r) is the rate of change in real value of an asset over a specified period of time. The inflation rate (i) is given by: i = n – r.

Usually the inflation rate in future is unknown at present, so there will be a n expected real interest rate (re) : re = n – ie, where ie is the expected inflation rate.

Also, the actual real interest rate ra can be given by ra = n - ia where ia is the actual inflation rate.

When the actual change in price level differs from expected, there will be a redistributive effect between providers and recipients of fixed future payments.

- Anticipated change in price level is expected (correctly).

- Unanticipated change in price level is unexpected or expected incorrectly.

- Under inflation, providers of fixed future payments (borrower) gain while the recipients (lender) lose. It’s because the interest rate of fixed future payment is bonded by expected inflation rate. When unanticipated inflation exist, the value of returning sum is less than expected in real terms (ia > ie, ra = n - ia < n - ie = re).

- Oppositely, under deflation, providers of fixed future payments (borrower) lose while the recipients (lender) gain.

Tuesday, 28 December 2010

Economics: National Income statistic II

Nominal GDP VS Real GDP

Nominal GDP (GDP at current market prices) is the GDP measures at market prices of the current period, i.e., GDP at current market prices = ΣPcQc, where Pc is the current market prices.

Real GDP (GDP at constant market prices) is the GDP measures at market prices of a specified base period chosen, i.e., GDP at constant market prices = ΣPbQc, where Pb is the current market prices.

It can be measured by revaluing the market price in base period or deflating the nominal GDP by a certain price indexes. Real GDP is a better measure of GDP since the effect of change in price level is eliminated so that change in real GDP implies change in aggregate output.

Per capita GDP/consumption = GDP/consumption divided by population, mainly used to show the living standard.

Full-employment GDP (Potential GDP) is a theoretical GDP when all resources are used efficiently. It eliminates the effect of misuse of resource and unemployment problem.

Demand side factor affecting actual GDP:

  • - C: increase in income/tax allowance or decrease in salaries rate increases consumption
  • - I: decrease in profit tax rate/interest rate increases investment
  • - Change in G, X, M affects GDP directly.

Supply factor affecting the potential GDP: quantity/quality increase in factors of production, technology, favourable economic policies, political stability, etc.

Uses of national income statistics

  1. 1) Assess economic performance of an economy
  2. 2) Reflect economic welfare (living standard) of a economy
  3. 3) Facilitate international comparison
  4. 4) Provide information for government to formulate economic policies, e.g. value-added of different industries shows that which sectors need more support.
  5. 5) Provide information for firm to make production and investment plans.

Limitations/weaknesses of national income statistics

  1. 1) Value of some unpaid services are excluded – underestimating economic welfare
  2. 2) Inaccurate estimation of illegal, unreported and non-marketed production
  3. 3) Value of leisure is excluded (more leisure time under the same GDP is preferred)
  4. 4) Undesirable effect of production is excluded (e.g. damaging the environment)
  5. 5) Change in general price level is ignored in nominal GDP
  6. 6) Population size is ignored in nominal GDP
  7. 7) Composition of output is ignored (e.g. only C, G relates to the economic welfare)
  8. 8) Income inequality not shown
  9. 9) Market value of a certain currency may not be unique
  10. 10) Time, e.g. durable serves for production more than the period of time but it’s not included.

General price level is the weighted average of price of all goods and services in the economy. The price index at base period is set at 100.

Consumer price index (CPI) is the price level of consumer goods and services generally purchased by domestic households in a specified period. In HK, CPI(A), (B) and (C) reflects the price level for lower, medium and higher income group, covering 50%, 30% and 10% of household respectively. Composite CPI reflects the price level of products generally purchased by all the above households.

Implicit price deflator of GDP shows the price level of goods and services related to GDP in a specified period.

GDP deflator of the current period = Nominal GDP / Real GDP * 100

CPI VS GDP deflator

  • - CPI covers consumer goods while GDP covers all goods and services related to GDP
  • - CPI has a more fixed weights (in HK, the weights are adjusted every 5 years) while GDP has variable weights, depends on the composition of GDP.
  • - CPI is a better indicator of living standard since the cost of living is related to those consumer goods and services.

Growth rate refers to (new-old)/old * 100%, while growth rate in GDP is approx. equal to growth rate in population * growth rate in per capita GDP.

Saturday, 25 December 2010

Chemistry : Introduction to carbon chemistry

Carbon chemistry

Uniqueness of carbon:

1) Ability to catenate into a long chain, i.e., forming stable bonds with itself steadily (C-C bond), Note that Si can’t catenate since Si-Si bond is weak.

2) Forming multiple bonds since it can process sp3, sp2 and sp hybridization

3) Forming 4 covalent bonds.

Nomenclature and expression:

- Condensed structural formula: omit C-C and C-H bond in the parent chain. E.g. CH3CH3.

Use bracket for branched chain, e.g. CH3CH(CH3)CH3

- Skeletal formula: omitting C atom, C-C bond and C-H bond.

Functional group is one or a group of toms that determines most properties of the compound.

A homologous series is a series of compounds that have the same functional group; each member differs from the next one by a –CH2- unit. For example, alkane: CH4, CH3CH3…

They have the same general formula, shows gradual change in physical properties and similar in chemical properties.

Gradual change in physical properties down the homologous series include: darker in colour, more viscous, less volatile, less flammable and burns with a more sootier flame.

There’re two types of hydrocarbons, aliphatic hydrocarbon is those who doesn’t contain a benzene ring while aromatic hydrocarbon has at least one benzene ring. Hydrocarbons with π-bond are called unsaturated hydrocarbons.

Functional group: (R represents H or alkyl group, X represents halogen atom)

1) Alkane is not a functional group, has a general formula of CnH2n+2 (RH).

2) Alkene has general formula CnH2n (R2C=CR2), it contains double bond(s).

3) Alkyne has general formula CnH2n-2 (RC≡CR), it contains triple bond(s)

4) Haloalkane has general formula CnH2n+1X (RX), it contains halogen atom(s).

5) Alkanol has general formula CnH2n+1OH (RO) it contains –OH group(s).

6) Alkanoic acid has general formula Cn-1H2n+1COOH (RCOOH)

7) Aromatic hydrocarbon contains a benzene ring or phenyl (C6H5-) group.

Basic nomenclature: prefix – parent – unsaturated form - suffix

1) Parent chain is the longest chain that contains the functional group, triple and double bond. From 1 to 8 carbon: meth-, eth-, prop-, but-, pent-, hex-, hept- and oct-. For example, C8H18 is called octane.

2) Assigning number to the carbon atom on the carbon chain, functional group and π-bond should be assigned a number which is the smallest possible. For example, CH3CH2OH, C is assigned 1 but not 2.

3) Suffix: the functional group; for example, CH3CH2COOH has suffix –oic acid. When the functional group does not has a unique position, numbers are assigned before suffix. For example there’re two butene, namely but-2-ene (CH3CH=CHCH3) and but-1-ene (CH2=CHCH2CH3), the double bond appears in the first and second C atom respectively.

4) Prefix: the substitutes, mainly branched chains, like CH3CHClCH is called 2-chloropropane, since it has 3 C atom on parent chain (prop-), has no functional group (-ane), and the Cl atom is on the second C atoms. When there’re more than one substitutes,, we use alphabetical order to arrange them.

5) The unsaturated form shows the existence of π-bonds. Double bond is shown by –en-, it there’re more than one double bonds, we use di-, tri- and tetra-, e.g. if there’re three double bond and 2 triple bond, then the unsaturated form is –triendiyne.

6) The name of functional group uses –yl, like CH3- is methyl and C2H5- is ethyl-

7) When there’re more than 1 function groups, -oic acid takes higher priority than –OH, then the –OH group will be the prefix.

8) For cycloalkanes, the functional group is assigned as the first C atoms.

More examples:

- CH3C(CH3)2CH2CH3 has 4 C atom on parent chain, no functional groups, and 2 methyl group on the second C atom, so it’s called 2,2-dimethylbutane

- CH3CH=CHCl has 3 C atoms on parent chain, belongs to alkene, and has 1 chlorine atom on the first C atom, so it’s called 1-chloroprop-1-ene.

- HOCH2CH2COOH is called 3-hydroxypropanoic acid.

- CH3C(CH3)=CBrCOOH is called 2-bromo-3methylbut-2-enoic acid.

- The figure shown is 1-methylhexene, since the C atom connected to methyl group and double bond is assigned as the first carbon atom.

- Benzene is cyclohex-1,3,5-triene.

Reactions of alkane:

1) Combustion – CnH2n+2+(3n+1)/2 O2→nCO2+(n+1)H2O, upon incomplete combustion, CO and C (unconsumed hydrocarbon) is produced, and sooty flame is observed. Combustion of alkane has made alkane into the main use of fuel.

2) Substitution (Halogenation):

- Initiation: Under UV light, X2 → 2X∙, X∙ refers to halogen free radicals.

- Chain reaction (propagation): RH (alkane) + X∙ → R∙ + HX and R + X2 → RX + X∙

- Termination occurs when two free radicals collides and combine: X∙+ X∙→X2, X∙+R→RX or R∙+R’∙→R2

- Under excess alkane, the major product is monosubstituted haloalkane and if halogen is in excess, haloalkanes with all H being substituted by halogen atoms will be the main product. For example, in excess Cl2, CH4 will eventually change into CCl4. If there’re excess CH4, then major product will be CH3Cl.

3) Cracking: Under heating of catalyst, when long-chain hydrocarbons pass through the catalyst, it cracks into shorter alkane, alkene and alkyne. It’s called catalytic cracking. It has the significant use of producing alkenes and extra fuels.


Reactions of alkene

1) Addition : When X2 is react with alkene in organic solvent, halogen atom are attached to the two C atom in the double bond. e.g.

It serves as test for unsaturation: Br2 in organic solvent. At the same time, alkenes under Pt/Pd/Rh/Ni as catalyst react with H2 to give alkanes.

2) Oxidation: CH2=CH2 + [O] + H2O → HOCH2CH2OH, the alkene is oxidized into a diol. It serves as a test for unsaturation: purple cold, diluted KMnO4/H+ become colourless when added to unsaturated hydrocarbon. Other oxidizing agents include KMnO4/OH- and OsO4.

Applications – fossil fuels

Coal is formed by dead land animals in a million years ago , covered by mud and under heat, pressure and effects of bacteria. Petroleum and natural gas is formed in the similar way, but it requires sea dead animals instead of that from land.

Uses of different fraction of petroleum

1) Refinery gas – fuel (LPG) 2) Petrol – Car fuel

3) Naphtha – raw material of town gas 4) Kerosene – domestic fuel, aircraft fuel

5) Diesel oil – fuel for heavy vehicles 6) Fuel oil – fuel for ships and power stations

7) Wax, lubricating oils – candles 8) Bitumen – Road construction, roofs

Exothermic reaction is the reaction that heat is released while heat is taken in during endothermic reaction.

Air pollutants

1) CO and C from incomplete combustion in cars, CO is toxic.

2) Unconsumed hydrocarbons from cars like benzene are carcinogenic.

3) Respirable suspended particle (RSP) reduces visibility and damage respiratory system.

4) Oxides of nitrogen (NOx) from car engines, gives acid rain (2NO2+H2O→HNO2+HNO3), irritate respiratory system and forms photochemical smog with unconsumed hydrocarbon.

5) SO2 from combustion of impure fuel, is irritating and form acid rain (SO2+H2O→H2SO3)

6) Heavy metal oxides (mainly PbO) from impurities: toxic

Solutions:

1) Catalytic convertors (Pt/Pd/Rh) engages complete combustion and convert CO, NOx into less harmful CO2 and N2.

2) Scrubbers or desulphurization systems in the power stations: SO2 is neutralized by CaO.

3) Electrostatic precipitators in power stations and particulate removal devices in motor vehicles remove particulates.

4) Using lead-free, low-sulphur content fuels for cards, low nitrogen oxide burners in power stations.


I've got some hard time to select those elementary reactions since it's hard to exclude some reaction when you're taking "addition" or other kinds of reactions. For example, KMnO4/H+ further oxidizes diols, so KMnO4/OH- is a better test for unsaturation, but it's not on the book.

Thursday, 23 December 2010

Economics: National Income statistic I

Macroeconomics – study on aggregate output and general price level

Stock and flow as measures of the economic variables: stocks is measured at an instant of time but flow is measured in a period of time. For example, wealth is a stock but income is a flow (measured “per month”, measuring income at a point of time is meaningless)

GDP and GNP as the measurement of aggregate output:

1) Gross domestic product is the total market value of production of all residential producing units (RPU) of a country of territory in a specified period (usually 1 year). RPU refers to individuals or organizations with engaged to product and maintain the economic interest at the territory. Note that GDP counts RPU as units, not individuals.

2) Gross national product is the total market value of production of all residents of a country of territory in a specified period. Residents refers to individuals which maintains the economic interest at the territory, irrespective to their nationality.

Stuffs that excluded in GDP:

1) Past inventories (out of the period) are not counted.

2) Second-hard goods since the production value is counted in its first transaction, and this prevents double counting.

3) Unpaid household services for self-consumption

4) Intermediate products since they’re not on sale on product market (only sold on factor market), and this prevents double counting.

5) Financial assets, capital gain and transfer payments, since they don’t involve production.

Approaches to measure GDP

1) Expenditure approach: C+I+G+(X-M) = C+I+G+NX

C: private consumption expenditure (on households and private non-profit institutions). Note that renting premises and owner-occupied premises are both counted in C.

I: Gross investment expenditure refers to:

- Gross fixed investment expenditure includes fixed capital like (all) building, construction, machinery, equipment, software, as well as transfer of ownership of land and buildings like stamp duties.

- Change in inventories

It can also be refers to Depreciation + Net investment expenditure.

G: government consumption expenditure refers to expenditure on consumption by government departments that do not engage in market activities (e.g., Fire Services Dept.) and non-profit quasi-government institutions (e.g., Hospital Authority). Expenditure of other government dept. will be counted as I.

X: Exports, include domestic export of goods, export of services and re-export of goods.

M: Imports, includes imports of services and goods. NX: Net exports

2) Production approach: sum of value-added of all RPU

Value-added = Value of output – value of intermediate consumption

e.g. A sales imports a bottle of wine at $60 and sold It at $80, then his value-added is $20.

3) Income approach: Rent + compensation of employees + capital consumption allowance + interest + profit (before tax)

Theoretically value obtained from the three approaches are the same.

Market price VS Factor cost

Since market price = factor cost + tax – subsidies, say P = C + t – s, then ΣPQ = ΣCQ + Σt – Σs, therefore GDP at factor cost = GDP at market price (abbreviated as GDP) – tax + subsidies.

GDP VS GNP

GNP = GDP + factor income earned by residents outside the economic territory (factor income from aboard) – factor income earned by non-residents within the economic territory (factor income paid aboard) = GDP + Net income from aboard (NIFA)

Monday, 20 December 2010

Notes on chem notes

I would like to follow the following sequences for my chemistry notes:
1) Nomenclature and properties
2) Reaction
3) Mechanism
4) Reigonochemistry
5) Applications
This follows the sequences of AL-chem topics, but I think the mechanism is greatly simplified since the concept of electrophile and nucleaophile is out syb.
For example unit 25-27 will be arranged like this
1) Homologus series
2) Nomenclature of alkane, alkene, alcohol carboxylic acid
3) Reaction of alkane
4) Reaction of alkene
5) Application : Fossil fuels
Also I want to include some extra reactions that would be useful:
e.g. the reaction that changes alkene to diols:
RCH=CHR + [O] + H2O -> R(CH(OH))2R + other product
Other than KMnO4/H+, OsO4 is also an alternative choice.

Saturday, 18 December 2010

18-12-10

同個fd玩鬥估賽果,如果我輸了的話要寫一篇TCG導論……

TCG (tatical card game) 的致勝之道不在於你有多強的卡牌,而是在於你卡組能做出必殺的機率高低,以及最差情況下的計劃。不要被電視蒙騙,沒有人永遠能在最後時刻抽出王牌反勝,但將這機會放到最大,你就是勝出的人。

分析TCG相信比RPG更為困難,因為能力很大程度上為運氣所主宰,因此在我看來卡牌遊戲的首要目的可以理解成「對抗命運」:當你一直抽爛牌時,你又會如何處理呢?
……

Tuesday, 14 December 2010

Multiple geometric summation

Recently I found that applications of geometric summation has been a popular topic among senior interschool competitions, the idea to solve them is actually easy, but only a few students are able to tackle them.

1)Recall: geometric summation
We mainly concerns infinite sum, so for all |r|<1, a+ar+ar^2+... = a(1+r+r^2+...) = a/(1-r)
Example: 1+1/2+1/4+... = 2.

2)A special case
We should note that 1/r+1/r^2+1/r^3+... = 1/(r-1).
Example: 1/8+1/64+1/512+... = 1/7.

3)Summation we uses the sigma sign to denote the summation.
e.g. Σ k (from 0 to 3) = 0+1+2+3 = 6
Double summation: Σ(x: from a to b)Σ(y: from c to d) f(x,y) = f(a,c)+f(a,c+1)+...+f(a+d)+f(a+1,c)+...+f(b,d)
Sometimes the inner summation's first and last term is bonded by the outer summation.
e.g. Σ (x: from a to c) Σ (y: from x to 2x) f(x,y) = f(a,a)+f(a,a+1)+...+f(a,2a)+f(a+1,a+1)+...+f(c,2c).

The following geometric summation, unless specified, adds from 1 to infinity.

4)Classic doubles
e.g. Evaluate Σ i / 2^i.
You may find that it's not a strict G.S. but we can solve it by G.S. by spliting terms.
1/2 + 2/4 + 3/8 + 4/16
= (1/2+1/4+1/8+1/16+...)+(1/4+1/8+1/16+...)+(1/8+1/16+...)+...
= (1)(1/2+1/4+1/8+1/16+...)+(1/2)(1/2+1/4+1/8+...)+(1/4)(1/2+1/4+1/8+...)+...
=(1+1/2+1/4+...)(1/2+1/4+1/8+...)
=(1)(2)=2

You may notice that G.S. turn sum to one terms, so double G.S. turns the sum into product of two terms.
When it's in forms of Σi/10^k, the result is k/(k-1)^2, which suits "product of two terms" and the lemma of special case on G.S..

5)Double summation in terms of summation
If we want to tackle double G.S. by summation we will have to use double summation.
e.g. Evaluate Σ i/3^i.
Σ i/3^i
=Σ 1/3^i + 1/3^i +...    (i terms)
=Σ (i:: from 1 to infinity) Σ (j: from 1 to i) 1/3^j
=Σ (i: from 1 to infinity) Σ (j from i to infinity) 1/3^j    (Note: this can be shown on a grpah.)
=Σ 1/(3-1)3^(i-1)
=(1/2) Σ 1/3^(i-1)
=(1/2)(3/(3-1))
=3/4

6)Further applications:
e.g. Evaluate 7/10^2 + 77/10^4 + 777/10^6+...
7/10^2 + 77/10^4 + 777/10^6 +...
=(7/10^2+7/10^4+7/10^6+...) + (70/10^4+70/10^6+...) + (700/10^6+700+10^8+...)+...
=7(1/10^2+1/10^4+...)+7/10(1/10^2+1/10^4+...)+7/100(1/10^2+1/10^4+...)=...
=7(1+1/10+1/100+...)(1/10^2+1/10^4+...)
=7(11/10)(1/99)
=7/90

7)Extension: multiple G.S.
e.g. Evaluate Σi^2 / 2^i.
Does it converge?     Yes since (i^2/2^i)' is eventually negative and tends to 0.
Use this identity: i^2 = 1+3+5+...+(2i-1).
1/2+4/4+9/8+16/16+...
=1/2+1/4+3/4+1/8+3/8+5/8+1/16+3/16+5/16+7/16+...
=(1/2+1/4+1/8+...)+3(1/4+1/8+...)+5(1/8+1/6)+...
=1+3/2+5/4+7/8+9/16+11/25+...
=(1+1/2+1/4+1/8+...)+2(1/2+1/4+1/8+...)+2(1/4+1/8+...)+...
=2+2+1+1/2+1/4+...=6
Note that three times of G.S. is used here.

8)More to explore
-Prove the special case of G.S.
-Evaluate Σ (n^2+n)/7^(n+1).
-Evaluate Σ i^3/3^i  and Σ i^4/4^i.
-Find the rage of y'<0 of the graph y = i^x/x^i, where x is a positive real. Hence or otherwise prove Σ (x : from 2 to fintiniy) Σ i^x/x^i converges.
-Show that (x-1)^xΣ i^x/x^i is an integer in terms of i) "product of n terms" and "calculation analysis"
-Explore more about polylogarithm function and this G.S.

fin.

Monday, 13 December 2010

Chemistry : Bond polarity and intermolecular forces

Bond polarity

Electronegativity describes the tendency of an atom or a functional group to attract e- (or electron density) towards itself and thus the tendency to form negative ions. The tendency of electronegativity across the periodic table is that it decrease down the period and increase along the group. The most electronegative atom is F, O and N, the least electronegative atom is alkali metal (Fr, Cs,…), so they are often referred as electropositive. Noble gas has electronegativity zero since it's assumed to be can't form bonds.

The trend across the group can be explained by increasing in atomic mass causes increase in p+, so that the attraction on e- bond pair increases.

The trend across the period can be explained by the increase in e- shell cause distance between nucleus and the e- bond pair increase, then the attraction decreases.

Concept of e- cloud: e- moving around the atom rather staying at a certain position. A electron cloud show the distribution that e- has a certain probability to appear there.

Consider a bond pair, X-Y. If X has a higher electronegativity, the e- bond pair is drawn towards X, then the electron cloud of the molecule is distorted to X (since e- is more likely to be appeared there), and X receives a partial negative charge, denoted by δ-, while Y receives a partial positive charge, denoted by δ+. The larger difference in electronegativity between X and Y, the higher partial charge received.

1) Pure ionic bond (electronegativity diff more than 2.0), the e- bond pair is greatly drawn to the electronegative atom, and the it receives a whole positive / negative charge. e.g., NaCl (Na is electropositive while Cl is very electronegative)

2) Ionic bond with covalent character: the e- bond pair is greatly drawn, but the charge is not separated greatly as pure ionic bond. e.g., MgCl2

3) Covalent bond with ionic character (polar covalent bond): the e- bond pair is slightly goes near to the electronegative atom. e.g., AlCl3, HCl, H2O

4) Pure covalent bond (electronegativity diff less than 0.5): the e- bond pair is nearly equally shared. E.g. C-H bond, all diatomic molecules like H2, Cl2.

Properties concerning different bonds:

- Pure ionic substances matter dissolves in water and pH is still 7.

- Ionic bond with covalent character / covalent bond with ionic character: also dissolves in water, but pH<7, due to dissociation. (Attracted by δ-O)

Dipole moment μ=Qd with unit D, where Q is the partial charge and d is the bond length. A larger diff in electronegativity mean larger Q and hence larger dipole moment. Dipole moment can be represented by  in the structural formula by the following arrow, pointing from δ+ to δ-. For example, the dipole moment in HCl is 1.1D.

The net dipole moment of a molecule is given by the vector sum of all dipole moment exist in the molecule. Note that even there's dipole moment in the molecule, the dipole moments can eliminate each other and cause no net dipole moment. For example, the dipole moment in CO2 is cancelled out each other, and it has no net dipole moment, similar to BF3 and CCl4. We can call these molecules as non-polar.

When there's a net dipole moment like NH3, CHCl3, H2O, SO2, we call the molecules polar.

By the rule of like dissolve like, those polar molecules are very soluble in water while non-polar molecules like CO2 are very insoluble in polar solvents like water.

In a polar molecule, the e- cloud is permanently distorted, and there's a partial charge. We say that a permanent dipole is formed.

In a non-polar molecule, the e- sometimes maybe distorted a bit (significantly less than permanent distortion), an instantaneous δ+ and δ- is created at the moment, and an instantaneous dipole is formed.

When a molecule with instantaneous/permanent dipole moves to a non-polar molecules, the e- clouds in the non-polar molecules may be distorted due to attraction/repulsion of charge from the dipole, and create δ+ and δ- in the non-polar molecules, then induced dipole is formed.

Intermolecular forces (often referred as wan der Waals' force)

1) Instantaneous dipole-induced dipole attraction, is the weakest among the three types of intermolecular forces but it appears in all molecules.

2) Permanent dipole-induced dipole attraction appears in mixture or solution where non-polar molecules are polarized by polar molecules through induction.

3) Permanent dipole-permanent dipole attraction, strength about 1/100 of covalent bond

Hydrogen bond is a strong attractive force between H attached to an electronegative atom and the lone pair on another electronegative atom. Usually the electronegative atom is F, O or N.

e.g., HF, H2O, CH3OH and NH3. Exceptional case: CHCl3 since there're 3 Cl atoms. The hydrogen bond is very strong (1/10 of covalent bond) since the e- is attracted by the electronegative atom in a great extent, then the proton of H is "naked" and has a very strong positive charge, which attracts the lone pairs. This explains the unusual high m.p./b.p. of hydrides of F, O and N than other atoms in group 5,6,7.

Factors affecting strength of intermolecular forces:

1) Polarizability: For a larger molecules/atoms, the attraction on outermost electron is weaker, then the e- cloud is more easily to be polarized. For example, m.p./b.p. of group 0 increases down the group since the size of e- cloud increase, then polarizability increases, then the instantaneous dipole-induced dipole attraction increase.

2) Shape of molecule: A straight chain allows greater contact among molecules, and hence greater attraction. E.g. b.p. of CH3(CH2)3CH3 is greater than CH3C(CH3)2CH3 though their molecular formula is the same (C5H12).

Water and ice: water attains highest density at 4˚C because ice adopts the open caged structure so that each H2O molecules forms 4 hydrogen bonds, and hence it has a very low density. Water starts to adopt the open cages structure when it's cooled under 4˚C, so the density increases from 0˚C to 4˚C. When it's heated over 4˚C, molecules gains K.E. so that the average separation increase, and hence lower density.

Other properties relating to intermolecular forces

1) Surface tension is caused by intermolecular force acting in all direction on the molecules, allowing it can form a tighten elastic surface. Liquids with stronger intermolecular forces tends to have greater surface tension.

2) Viscosity depends on the strength of intermolecular forces and the tendency of molecules to become entangled with each other. Usually molecules with longer and branched chain is entangled easier. For example, propan-1,2,3-triol (glycerol) has a significantly higher viscosity than ethanol because of its branched shape and high ability to form hydrogen bonds. Yet ethanol has a higher viscosity than propanone since propanone can't form hydrogen bond.

3) Melting and boiling point relates to the strength of intermolecular forces. For example, the boiling point of C3H8 < CH3OCH3 (polar) < CH3OH (hydrogen bond).

4) Ease of evaporation: molecules in liquids have to do work against atmospheric pressure and intermolecular force to vaporize. Stronger intermolecular force reduces the ease of vaporization.

5) Solubility in water: molecules that can form hydrogen bond is greatly soluble since forming of hydrogen bond helps the dissolving process.

Polar molecules which do not form hydrogen bonds are fairly soluble since less hydrogen bond can be formed between them.

Non-polar molecules is insoluble in water due to difference in strength of intermolecular forces between water and the non-polar molecules.

Saturday, 11 December 2010

Chemistry : Shape of molecules

Valence Shell Electron Pair Repulsion (VSEPR) Theory:

1) e- pairs in central atom tends to get as far as possible to minimize electrostatic repulsion between e- pairs in valence shell

2) Both bonded and lone pair is involved.

The order of repulsion: LP-LP > LP-BP > BP-BP (LP: lone pair, BP: bond pair)

Wedge-shaped bonding lines: solid wedge implies the atom is in front of the plane, while a dotted one implies the atom is behind the plane.

1) Linear (2BP), e.g. CO2 (O=C=O), BeCl2, ethyne (H-C≡C-H)

2) Trigonal planar (3BP), e.g. BF3

3) V-shaped (2BP-1LP), one of the BP replaced by LP, bond angle slightly smaller than 3BP. e.g., NO2-, SO2, O3

4) Tetrahedral (4BP), e.g. CH4, CH2X2, PO43-, SO42-, ClO4-, NH4+ (one of them is dative covalent bond)

5) Trigonal pyramidal (3BP-1LP), one of the BP replaced by LP, bond angle slightly smaller than 4BP. e.g., NH3, PCl3, H3O+

6) V-shaped (2BP-2LP), two of the BP replaced by LP, the plane of BP is perpendicular to the plane of LP. e.g., H2O. OF2, NH2-

7) Trigonal bipyrmidal (5BP), three of them on the triangular plane and the remaining two facing in opposite sides, perpendicular to the plane. e.g., PCl5.

8) Linear (2BP-3LP): the LP are on the equatorial triangular plane. This is a special case for XeF2.

9) Octahedral (6BP), e.g., SF6, complexes

10) Square pyramidal (5BP-1LP), e.g., ClF5, BrF5

11) Square planar (4BP-2LP), e.g., XeF4, [Cu(NH3)4]2+

Hybridization theory: sp3 forms a tetrahedral shape around the central atom and the sp2 forms a trigonal planar shape.

Some atoms can break the octet rule. For example, S under O.N. of +6, forms 6 bond like SO42-, P can form 5 bonds like PCl5, and Cr under O.N. of +6 like [CrO4]2-. Xe forms bond with halides without eliminating its electron on the outermost shell, and it can form up to 4 bonds. e.g., XeF2 and XeF4.

Carbon structure

1) Diamond – each C connected to four C

2) Graphite – hexagonal planar layered structure, each layer is connected by weak Wan der Waals’ force

3) SiC (Silicon carbide) – each Si is attached to four C and each C is attached to four Si

4) SiO2 (quartz) – each Si is connected to four O and each O is connected to two Si

5) Fullerene group: macromolecules formed by C.

6) Buckminsterfullerene (C60) has some special properties:

-Semi-conductor (delocalized π-bond gives delocalized e-), “Paper battery”

-Medical capsule (capturing compounds inside it, e.g., He@C60

-Dissolves in toluene to gives pink sol.

-Addition reaction is possible

-K3C60 can be a superconductor

Sunday, 5 December 2010

Chemistry : Electrolysis

Electrolysis is the reaction that occurs when electricity pass through the electrolyte in aqueous or molten state. Electrolytic cell is where electrolysis occurs.

Note that in electrolytic cell, negative terminal is cathode while positive terminal is anode (interchanged with chemical cell), also usually inert electrodes is used.

Dissociation of water: H2O→H++OH- (reversible reaction)

The three factor affecting preferential discharge of aqueous ions:

1)       Position of ions in the E.C.S. (Note that NO3- and SO42- is even lower than Cl-.)

Lower position of cations in E.C.S. is easier to be discharged, while higher position of anions in E.C.S. is easier to be discharged.

e.g. Acidified water (H+ used to conduct electricity): In cathode, there’re only one species of ion (H+) so H2 is released. In anode, there’re two species of ion: SO42- and OH-, since OH- has higher position in E.C.S., O2 is given off. Overall reaction: 2H2O→2H2+O2

e.g.2: Very dilute NaCl (~0.1M), H+ is preferentially discharged than Na+, and OH- is preferentially discharged than Cl-, Overall reaction: 2H2O→2H2+O2.

In both cases, water continuously dissociates to H+ and OH-, at cathode there’re excess OH- so it’s alkaline, while there’re excess H+ at anode so it’s acidic around the anode.

e.g.3: CuSO4, OH- is preferentially discharged, and Cu2+ is preferentially discharged, so there’s Cu formed on cathode. Blue colour fades due to loss of Cu2+.

2)       Concentration factor: when the two ions has similar position in E.C.S., ions with high concentration are preferentially discharged.

e.g. Conc. NaCl: In anode, though Cl- is lower than OH-, but it has a high concentration so it’s discharged and give Cl2 (since Cl2 attacks Pt, Pt electrode can’t be used). I- is preferentially discharged at any concentration, while Br- and Cl- preferentially discharge only when it’s concentrated. At anode, halides dissolves in water to form acidic solution, so solution around anode is acidic.

3)       Electrodes: In conc. solution, Na+ is preferentially discharged and dissolves in Hg to give stable sodium amalgam (Na/Hg). e.g. in conc. NaCl with Hg cathode, at cathode Na+ is preferentially discharged: Na++e-+Hg→Na/Hg, then the amalgam reacts with water: 2Na/Hg+2H2O→2NaOH+H2+2Hg, overall reaction: 2Na++2Cl-+2Hg→2Na/Hg+Cl2. The solution become more dilute.

Applications

-          Refining Cu: impure Cu at anode and pure Cu at cathode in CuSO4; The impure copper changes to ions, but only Cu2+ is preferentially discharged to form Cu at cathode.

-          Electroplating: Plating metal at anode, object at cathode, aq. Solution with salt of plating metal as electrolyte. Factor affecting its quality: lower concentration, acidic solution, brighteners and leveling agents, low current, similar shape with the object, etc.

Environmental concerns on electroplating: acids/alkalis, heavy metal, CN- in water.

Electrochemistry is now finished.

Saturday, 4 December 2010

Chemistry : Chemical Cell II

Redox in primary cells

-          Oxidation occurs at anode, and reduction occurs in cathode. Since anode gains e- and cathode loses e-, we can deduce that the e- flow is from anode to cathode in external circuit and cathode to anode in the internal circuit.

-          Zinc carbon cell: There’re four layers of chemical carbon rod (cathode), MnO2, moist paste of NH4Cl (electrolyte) and Zn case (anode).

Oxidation at anode: Zn→Zn2++2e-, Reduction at cathode: 2NH4++2e-→2NH3+H2. Since H2 is explosive, they’re oxidized by MnO2: 2MnO2+H2→Mn2O3+H2O. NH3 form complexes with the ions: Zn2++2NH3+2Cl-→Zn(NH3)2Cl2, so the overall equation is  2MnO2+2NH4Cl+Zn→Zn(NH3)2Cl2+Mn2O3+H2O

Uses: low voltage supply (small radios, remotes)

Disadvantage: leakage since Zn is consumed directly; voltage drops significantly since gas is accumulated in the cell.

-          Alkaline Manganese cell: The layers are: MnO2 and carbon powder(cathode), KOH (electrolyte) and Zn (anode). In this case, Zn + 2OH-→ZnO+H2O+2e-,

2MnO2+H2O+2e-→Mn2O3+2OH-, the overall reaction is Zn +2MnO2→ZnO+Mn2O3

Uses: higher capacity like camera and motors.

Disadvantage: The leakage of alkaline contents is irritate/corrosive, may form crystal and harm electrical component.

-          Silver oxide cells (“Button” cells): AgO(cathode), KOH(electrolyte), Zn powder(anode)

Uses: portable small devices such as pacemakers, calculators

Secondary Cells

-          Lithium ion cell: Li+ migrate between cathode and anode between graphite sheets during charging (cathode to anode) and discharging (anode to cathode). It has a large applications like laptops since it’s light and has high energy density.

-          Nickel metal hydride (NiMH): It has metal hydride as anode and Ni(OH)2 as cathode, KOH as the electrolyte. It has a quite high energy density and used as cells like Zinc-carbon cells and alkaline manganese cells. Currently it’s replacing by NiCd (nickel-cadmium) cell with more reliable and low temperature performance.

-          Lead-acid accumulator (known as car battery): Pb as anode and PbO2 as cathode, while H2SO4 is the electrolyte. At anode, Pb+SO42-→PbSO4+2e- and PbO2+4H++SO42-+2e-

→PbSO4+H2O at cathode. Overall reaction: Pb+SO42-+PbO2+4H++SO42-→2PbSO4+2H2O

The reaction is reversible; equilibrium goes to RHS when discharging and LHS when charging. Note that after some discharging, both anode and cathode becomes PbSO4, which cause dropping in voltage.

Theoretically it is eternally rechargeable, but in reality PbSO4 may fall off from the Pb plates which can’t be recharge again.

-          Fuel cell: change fuel’s chemical energy to electrical energy. A fuel and oxidant (usually O2) is used. There’re many type of fuel cell such as alkaline fuel cell, phosphoric acid fuel cell, molten carbonate fuel cell, solid oxide fuel cell, proton exchange membrane fuel cell and direct methanol cell.

Alkaline fuel cell: insert H2 and O2, OH- as electrolyte, at anode: H2+2OH-→2H2O+2e-, at cathode, O2+2H2O+4e-→4OH-, overall reaction: 2H2+O2→2H2O

Direct methanol fuel cell: at anode: CH3OH+H2O→CO2+6H++6e-, at anode: 3O2+12H++12e-→6H2O, overall reaction: 2CH3OH+3O2→2CO2+4H2O

Advantage: highly efficient and environmental friendly (CO2 and H2O as the only product)

Chemistry : Chemical Cell I

Simple Chemical cells

Primary and secondary cells refers to not rechargeable and rechargeable cells.

Anode is the electrode from which e- flows into the external circuit.

Cathode is the electrode from which e- flows from the external circuit.

Electrolyte is the medium to allow ionic conduction between the two electrodes.

Capacity is the quantity of electricity delivered under certain conditions, with unit mAh.

Discharge is the conversion from chemical energy to electrical energy. There’re two typical discharge curve “flat”: voltage remains steady during discharge; “sloping” voltage drop gradually during discharge.

Service life is the useful period of the cell before the voltage drops to a certain value (0.8V).

Cycle life refers to the number of recharge available before it can deliver sufficient energy by a secondary cell.

Shell life is the duration of storage for a (primary) cell to maintain the same capacity.

A simple chemical cell model:

Mg and Cu strip in a CuSO4 solution/inserted in a lemon/put a filter paper soaked with NaCl and put between the two metals, and connected to the external circuit.

In all three cases:

- Mg dissolves in the solution, that is, Mg→Mg2++2e-.

- e- from Mg goes to the external circuit and flows to the Cu strip. Excess e- in Cu strip is obtained by the Cu2+, and they are reduced to metal form: Cu2++2e-→Cu

- Overall equation: Cu2++Mg→Mg2++Cu, the e- flow produces current.

- Identifying: Mg is anode, Cu is cathode, and CuSO4 is the electrolyte.

Voltage obtained by the cell is given by the difference of position in electrochemical series. Larger difference gives larger voltage. Note that the negative terminal of voltmeter is connected to cathode if the voltage is negative.

However there’s direct displacement between Mg and Cu in the above cells, then less mobile e- flows to the circuit, which make the cells less efficient.

We improve the cells by separating two half cells, containing different solution and one electrode, connected by a salt bridge (usually filter paper soaked with KNO3 or NaCl)

Roles of salt bridge:

- Allow ions to move between the two half cells to complete the circuit.

- Provide ions for the half cells to prevent excess charged ions accumulating and cause the reaction to stop.

Inert electrodes (usually graphite or Pt): they do not react with the solutions, but the chemical cells still happen. e.g., one of the beaker is Fe2(SO4)3 and another beaker is KI. 2I-→I2+2e-, the e- flows to the external circuit and goes to Fe2(SO4)3 solution, and iron(III) ion is reduced to iron(II) ion: Fe3++e-→Fe2+. We can predict the preference of losing e- by E.C.S.

Daniell cell is the first portable cells developed in 1835. The cell is constructed by a two half cells, one inside another and separated by a porous pot; Zn and ZnSO4 at anode while Cu and CuSO4 at cathode. The overall reaction is Zn+Cu2+→Zn2++Cu. Note that the porous pot does not provide ions, but it prevents direct displacement and allow ions to move through the small holes in the porous pot.

Thursday, 2 December 2010

Conical Pendulum

Describe quantitatively when the conical pendulum spins faster; what's the angle θ between the string and the vertical tube?
Quantity:
-          L: length of the string
-          r: radius of circular motion
-          T = Mg, tension produced
-          mg: mass of the ball on the string
By observation it's obvious that θ tends to 90 degrees.
Approach 1:
(1): Tcosθ = mv2/r
(2): Tsinθ = mg
(2)/(1): tanθ = v2/rg = v2/Lgsinθ
tanθsinθ = v2/Lg
When θ is between 0 and 90 degrees, tanθ and sinθ has the same behavior, L, g being fixed, then when v increases, θ must increase (and tends to 90 degrees)
Approach 2:
Tcosθ = mrω2
When v increases, ω also increase. Then cosθ will increase.
Now we'll find a dilemma:
By Tsinθ = Mgsinθ = mg, we can see when sinθ increase, Mg and mg is still fixed, which leads to a unbalanced equation.

Can you solve the dilemma?